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x^2=213
We move all terms to the left:
x^2-(213)=0
a = 1; b = 0; c = -213;
Δ = b2-4ac
Δ = 02-4·1·(-213)
Δ = 852
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{852}=\sqrt{4*213}=\sqrt{4}*\sqrt{213}=2\sqrt{213}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{213}}{2*1}=\frac{0-2\sqrt{213}}{2} =-\frac{2\sqrt{213}}{2} =-\sqrt{213} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{213}}{2*1}=\frac{0+2\sqrt{213}}{2} =\frac{2\sqrt{213}}{2} =\sqrt{213} $
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